1103223113 has 4 divisors (see below), whose sum is σ = 1103318400. Its totient is φ = 1103127828.

The previous prime is 1103223097. The next prime is 1103223119. The reversal of 1103223113 is 3113223011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3113223011 = 109 ⋅28561679.

It is a cyclic number.

It is not a de Polignac number, because 1103223113 - 2⁴ = 1103223097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1103223091 and 1103223100.

It is not an unprimeable number, because it can be changed into a prime (1103223119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27413 + ... + 54386.

It is an arithmetic number, because the mean of its divisors is an integer number (275829600).

Almost surely, 2^1103223113 is an apocalyptic number.

It is an amenable number.

1103223113 is a deficient number, since it is larger than the sum of its proper divisors (95287).

1103223113 is an equidigital number, since it uses as much as digits as its factorization.

1103223113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 95286.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 1103223113 is about 33214.8026187120. The cubic root of 1103223113 is about 1033.2873612453.

Adding to 1103223113 its reverse (3113223011), we get a palindrome (4216446124).

It can be divided in two parts, 110 and 3223113, that added together give a palindrome (3223223).

The spelling of 1103223113 in words is "one billion, one hundred three million, two hundred twenty-three thousand, one hundred thirteen".