Base | Representation |
---|---|
bin | 10000000011100001110… |
… | …100101110011100110001 |
3 | 10220110210220012112221102 |
4 | 100003201310232130301 |
5 | 121034024340314441 |
6 | 2202503230534145 |
7 | 142465545003563 |
oct | 20034164563461 |
9 | 3813726175842 |
10 | 1103300323121 |
11 | 3959a82a6667 |
12 | 1599b1067355 |
13 | 8006b7716a9 |
14 | 3b585929333 |
15 | 1da755b969b |
hex | 100e1d2e731 |
1103300323121 has 4 divisors (see below), whose sum is σ = 1161368761200. Its totient is φ = 1045231885044.
The previous prime is 1103300323079. The next prime is 1103300323241. The reversal of 1103300323121 is 1213230033011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1103300323121 - 214 = 1103300306737 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1103300323093 and 1103300323102.
It is not an unprimeable number, because it can be changed into a prime (1103300343121) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29034219011 + ... + 29034219048.
It is an arithmetic number, because the mean of its divisors is an integer number (290342190300).
Almost surely, 21103300323121 is an apocalyptic number.
It is an amenable number.
1103300323121 is a deficient number, since it is larger than the sum of its proper divisors (58068438079).
1103300323121 is an equidigital number, since it uses as much as digits as its factorization.
1103300323121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 58068438078.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 1103300323121 its reverse (1213230033011), we get a palindrome (2316530356132).
The spelling of 1103300323121 in words is "one trillion, one hundred three billion, three hundred million, three hundred twenty-three thousand, one hundred twenty-one".
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