Base | Representation |
---|---|
bin | 10000000011100010011… |
… | …110010001000111001011 |
3 | 10220110211122200211001101 |
4 | 100003202132101013023 |
5 | 121034040132304003 |
6 | 2202504300202231 |
7 | 142466036400526 |
oct | 20034236210713 |
9 | 3813748624041 |
10 | 1103311213003 |
11 | 395a0346436a |
12 | 1599b4839377 |
13 | 80070ab52cc |
14 | 3b587161bbd |
15 | 1da7651b11d |
hex | 100e27911cb |
1103311213003 has 8 divisors (see below), whose sum is σ = 1103957056800. Its totient is φ = 1102665475968.
The previous prime is 1103311212919. The next prime is 1103311213073. The reversal of 1103311213003 is 3003121133011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1103311213003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1103311213073) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30185443 + ... + 30221971.
It is an arithmetic number, because the mean of its divisors is an integer number (137994632100).
Almost surely, 21103311213003 is an apocalyptic number.
1103311213003 is a deficient number, since it is larger than the sum of its proper divisors (645843797).
1103311213003 is a wasteful number, since it uses less digits than its factorization.
1103311213003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 53381.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 1103311213003 its reverse (3003121133011), we get a palindrome (4106432346014).
The spelling of 1103311213003 in words is "one trillion, one hundred three billion, three hundred eleven million, two hundred thirteen thousand, three".
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