1103430443113 has 4 divisors (see below), whose sum is σ = 1139024973568. Its totient is φ = 1067835912660.

The previous prime is 1103430443081. The next prime is 1103430443191. The reversal of 1103430443113 is 3113440343011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1103430443113 - 2⁵ = 1103430443081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1103430443813) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17797265181 + ... + 17797265242.

It is an arithmetic number, because the mean of its divisors is an integer number (284756243392).

Almost surely, 2^{1103430443113} is an apocalyptic number.

It is an amenable number.

1103430443113 is a deficient number, since it is larger than the sum of its proper divisors (35594530455).

1103430443113 is an equidigital number, since it uses as much as digits as its factorization.

1103430443113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35594530454.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1103430443113 its reverse (3113440343011), we get a palindrome (4216870786124).

The spelling of 1103430443113 in words is "one trillion, one hundred three billion, four hundred thirty million, four hundred forty-three thousand, one hundred thirteen".