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11034373813747 = 199771924930881
BaseRepresentation
bin1010000010010010001111…
…1011100111010111110011
31110001212122111001100012021
42200210203323213113303
52421241344144014442
635245042113412311
72216131032604624
oct240444373472763
943055574040167
1011034373813747
113574719396a49
1212a265156a097
136206c99b100b
142a20d083da4b
15142069297e67
hexa0923ee75f3

11034373813747 has 16 divisors (see below), whose sum is σ = 11627999460000. Its totient is φ = 10442036920320.

The previous prime is 11034373813739. The next prime is 11034373813751. The reversal of 11034373813747 is 74731837343011.

It is a cyclic number.

It is not a de Polignac number, because 11034373813747 - 23 = 11034373813739 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11034373813694 and 11034373813703.

It is not an unprimeable number, because it can be changed into a prime (11034373853747) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 357303747 + ... + 357334627.

It is an arithmetic number, because the mean of its divisors is an integer number (726749966250).

Almost surely, 211034373813747 is an apocalyptic number.

11034373813747 is a deficient number, since it is larger than the sum of its proper divisors (593625646253).

11034373813747 is a wasteful number, since it uses less digits than its factorization.

11034373813747 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51126.

The product of its (nonzero) digits is 3556224, while the sum is 52.

The spelling of 11034373813747 in words is "eleven trillion, thirty-four billion, three hundred seventy-three million, eight hundred thirteen thousand, seven hundred forty-seven".

Divisors: 1 19 977 18563 19249 30881 365731 586739 18806273 30170737 357319187 573244003 594428369 11294139011 580756516513 11034373813747