Base | Representation |
---|---|
bin | 1010000010010010001111… |
… | …1011100111010111110011 |
3 | 1110001212122111001100012021 |
4 | 2200210203323213113303 |
5 | 2421241344144014442 |
6 | 35245042113412311 |
7 | 2216131032604624 |
oct | 240444373472763 |
9 | 43055574040167 |
10 | 11034373813747 |
11 | 3574719396a49 |
12 | 12a265156a097 |
13 | 6206c99b100b |
14 | 2a20d083da4b |
15 | 142069297e67 |
hex | a0923ee75f3 |
11034373813747 has 16 divisors (see below), whose sum is σ = 11627999460000. Its totient is φ = 10442036920320.
The previous prime is 11034373813739. The next prime is 11034373813751. The reversal of 11034373813747 is 74731837343011.
It is a cyclic number.
It is not a de Polignac number, because 11034373813747 - 23 = 11034373813739 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11034373813694 and 11034373813703.
It is not an unprimeable number, because it can be changed into a prime (11034373853747) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 357303747 + ... + 357334627.
It is an arithmetic number, because the mean of its divisors is an integer number (726749966250).
Almost surely, 211034373813747 is an apocalyptic number.
11034373813747 is a deficient number, since it is larger than the sum of its proper divisors (593625646253).
11034373813747 is a wasteful number, since it uses less digits than its factorization.
11034373813747 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51126.
The product of its (nonzero) digits is 3556224, while the sum is 52.
The spelling of 11034373813747 in words is "eleven trillion, thirty-four billion, three hundred seventy-three million, eight hundred thirteen thousand, seven hundred forty-seven".
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