110399113 has 4 divisors (see below), whose sum is σ = 120435408. Its totient is φ = 100362820.

The previous prime is 110399111. The next prime is 110399117. The reversal of 110399113 is 311993011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311993011 = 11 ⋅28363001.

It is a cyclic number.

It is not a de Polignac number, because 110399113 - 2¹ = 110399111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110399111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5018131 + ... + 5018152.

It is an arithmetic number, because the mean of its divisors is an integer number (30108852).

Almost surely, 2^110399113 is an apocalyptic number.

It is an amenable number.

110399113 is a deficient number, since it is larger than the sum of its proper divisors (10036295).

110399113 is a wasteful number, since it uses less digits than its factorization.

110399113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10036294.

The product of its (nonzero) digits is 729, while the sum is 28.

The square root of 110399113 is about 10507.0982197750. The cubic root of 110399113 is about 479.7207765496.

The spelling of 110399113 in words is "one hundred ten million, three hundred ninety-nine thousand, one hundred thirteen".