110399924049 has 4 divisors (see below), whose sum is σ = 147199898736. Its totient is φ = 73599949364.

The previous prime is 110399924029. The next prime is 110399924053. The reversal of 110399924049 is 940429993011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110399924049 - 2⁵ = 110399924017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110399923992 and 110399924010.

It is not an unprimeable number, because it can be changed into a prime (110399924029) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18399987339 + ... + 18399987344.

It is an arithmetic number, because the mean of its divisors is an integer number (36799974684).

Almost surely, 2^110399924049 is an apocalyptic number.

It is an amenable number.

110399924049 is a deficient number, since it is larger than the sum of its proper divisors (36799974687).

110399924049 is an equidigital number, since it uses as much as digits as its factorization.

110399924049 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36799974686.

The product of its (nonzero) digits is 629856, while the sum is 51.

The spelling of 110399924049 in words is "one hundred ten billion, three hundred ninety-nine million, nine hundred twenty-four thousand, forty-nine".