11040033113 has 4 divisors (see below), whose sum is σ = 11420723940. Its totient is φ = 10659342288.

The previous prime is 11040033091. The next prime is 11040033139. The reversal of 11040033113 is 31133004011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6267572224 + 4772460889 = 79168^2 + 69083^2 .

It is a cyclic number.

It is not a de Polignac number, because 11040033113 - 2¹⁰ = 11040032089 is a prime.

It is a super-2 number, since 2×11040033113² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11040033091 and 11040033100.

It is not an unprimeable number, because it can be changed into a prime (11040033413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190345370 + ... + 190345427.

It is an arithmetic number, because the mean of its divisors is an integer number (2855180985).

Almost surely, 2^11040033113 is an apocalyptic number.

It is an amenable number.

11040033113 is a deficient number, since it is larger than the sum of its proper divisors (380690827).

11040033113 is an equidigital number, since it uses as much as digits as its factorization.

11040033113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 380690826.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 11040033113 its reverse (31133004011), we get a palindrome (42173037124).

The spelling of 11040033113 in words is "eleven billion, forty million, thirty-three thousand, one hundred thirteen".