Base | Representation |
---|---|
bin | 10000000100001100111… |
… | …110101000111110100001 |
3 | 10220112200100120112201111 |
4 | 100010030332220332201 |
5 | 121042020212424213 |
6 | 2203103133103321 |
7 | 142522516034215 |
oct | 20041476507641 |
9 | 3815610515644 |
10 | 1104024342433 |
11 | 396239a61031 |
12 | 159b73627b41 |
13 | 8015577079c |
14 | 3b613b56945 |
15 | 1dab8e33a3d |
hex | 1010cfa8fa1 |
1104024342433 has 8 divisors (see below), whose sum is σ = 1104595240320. Its totient is φ = 1103453589840.
The previous prime is 1104024342431. The next prime is 1104024342437. The reversal of 1104024342433 is 3342434204011.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1104024342433 - 21 = 1104024342431 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1104024342395 and 1104024342404.
It is not an unprimeable number, because it can be changed into a prime (1104024342431) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 17219191 + ... + 17283187.
It is an arithmetic number, because the mean of its divisors is an integer number (138074405040).
Almost surely, 21104024342433 is an apocalyptic number.
It is an amenable number.
1104024342433 is a deficient number, since it is larger than the sum of its proper divisors (570897887).
1104024342433 is an equidigital number, since it uses as much as digits as its factorization.
1104024342433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72647.
The product of its (nonzero) digits is 27648, while the sum is 31.
Adding to 1104024342433 its reverse (3342434204011), we get a palindrome (4446458546444).
The spelling of 1104024342433 in words is "one trillion, one hundred four billion, twenty-four million, three hundred forty-two thousand, four hundred thirty-three".
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