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1104025243513 = 8912404778017
BaseRepresentation
bin10000000100001101000…
…010000100111101111001
310220112200102021022202211
4100010031002010331321
5121042020430243023
62203103204255121
7142522526506243
oct20041502047571
93815612238684
101104025243513
1139623a517025
12159b739a14a1
13801559c797a
143b613d0d093
151dab9060a0d
hex1010d084f79

1104025243513 has 4 divisors (see below), whose sum is σ = 1116430021620. Its totient is φ = 1091620465408.

The previous prime is 1104025243487. The next prime is 1104025243567. The reversal of 1104025243513 is 3153425204011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 312713587264 + 791311656249 = 559208^2 + 889557^2 .

It is a cyclic number.

It is not a de Polignac number, because 1104025243513 - 25 = 1104025243481 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1104025243583) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6202388920 + ... + 6202389097.

It is an arithmetic number, because the mean of its divisors is an integer number (279107505405).

Almost surely, 21104025243513 is an apocalyptic number.

It is an amenable number.

1104025243513 is a deficient number, since it is larger than the sum of its proper divisors (12404778107).

1104025243513 is an equidigital number, since it uses as much as digits as its factorization.

1104025243513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12404778106.

The product of its (nonzero) digits is 14400, while the sum is 31.

The spelling of 1104025243513 in words is "one trillion, one hundred four billion, twenty-five million, two hundred forty-three thousand, five hundred thirteen".

Divisors: 1 89 12404778017 1104025243513