Base | Representation |
---|---|
bin | 1010000010101000110010… |
… | …0100000101111110001011 |
3 | 1110002110021010221221211011 |
4 | 2200222030210011332023 |
5 | 2421341242100110403 |
6 | 35251522330544351 |
7 | 2216434001332606 |
oct | 240521444057613 |
9 | 43073233857734 |
10 | 11040424222603 |
11 | 3577243717746 |
12 | 12a385b8980b7 |
13 | 6211523492b9 |
14 | 2a250621133d |
15 | 1422c053ba6d |
hex | a0a8c905f8b |
11040424222603 has 4 divisors (see below), whose sum is σ = 11520442667088. Its totient is φ = 10560405778120.
The previous prime is 11040424222559. The next prime is 11040424222679. The reversal of 11040424222603 is 30622242404011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11040424222603 - 213 = 11040424214411 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11040424226603) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 240009222208 + ... + 240009222253.
It is an arithmetic number, because the mean of its divisors is an integer number (2880110666772).
Almost surely, 211040424222603 is an apocalyptic number.
11040424222603 is a deficient number, since it is larger than the sum of its proper divisors (480018444485).
11040424222603 is an equidigital number, since it uses as much as digits as its factorization.
11040424222603 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 480018444484.
The product of its (nonzero) digits is 18432, while the sum is 31.
Adding to 11040424222603 its reverse (30622242404011), we get a palindrome (41662666626614).
The spelling of 11040424222603 in words is "eleven trillion, forty billion, four hundred twenty-four million, two hundred twenty-two thousand, six hundred three".
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