1104043341131 has 8 divisors (see below), whose sum is σ = 1191770923680. Its totient is φ = 1019626233472.

The previous prime is 1104043341127. The next prime is 1104043341209. The reversal of 1104043341131 is 1311433404011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1104043341131 - 2² = 1104043341127 is a prime.

It is a super-2 number, since 2×1104043341131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1104043341131.

It is not an unprimeable number, because it can be changed into a prime (1104043349131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 827618030 + ... + 827619363.

It is an arithmetic number, because the mean of its divisors is an integer number (148971365460).

Almost surely, 2^{1104043341131} is an apocalyptic number.

1104043341131 is a deficient number, since it is larger than the sum of its proper divisors (87727582549).

1104043341131 is a wasteful number, since it uses less digits than its factorization.

1104043341131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1655237445.

The product of its (nonzero) digits is 1728, while the sum is 26.

Adding to 1104043341131 its reverse (1311433404011), we get a palindrome (2415476745142).

The spelling of 1104043341131 in words is "one trillion, one hundred four billion, forty-three million, three hundred forty-one thousand, one hundred thirty-one".