Search a number
-
+
11041312355353 = 71577330336479
BaseRepresentation
bin1010000010101100000110…
…0000000011010000011001
31110002112120001010202220201
42200223001200003100121
52421400101430332403
635252150414422201
72216465004334120
oct240530140032031
943075501122821
1011041312355353
113577659a83a55
1212a3a69201961
13621264349237
142a258c15cab7
151423234c221d
hexa0ac1803419

11041312355353 has 4 divisors (see below), whose sum is σ = 12618642691840. Its totient is φ = 9463982018868.

The previous prime is 11041312355341. The next prime is 11041312355363. The reversal of 11041312355353 is 35355321314011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11041312355353 - 29 = 11041312354841 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11041312355363) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 788665168233 + ... + 788665168246.

It is an arithmetic number, because the mean of its divisors is an integer number (3154660672960).

Almost surely, 211041312355353 is an apocalyptic number.

It is an amenable number.

11041312355353 is a deficient number, since it is larger than the sum of its proper divisors (1577330336487).

11041312355353 is an equidigital number, since it uses as much as digits as its factorization.

11041312355353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1577330336486.

The product of its (nonzero) digits is 81000, while the sum is 37.

Adding to 11041312355353 its reverse (35355321314011), we get a palindrome (46396633669364).

The spelling of 11041312355353 in words is "eleven trillion, forty-one billion, three hundred twelve million, three hundred fifty-five thousand, three hundred fifty-three".

Divisors: 1 7 1577330336479 11041312355353