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1104131244323 = 3469318285167
BaseRepresentation
bin10000000100010011010…
…110011100000100100011
310220112221210201201112202
4100010103112130010203
5121042230044304243
62203121512243415
7142525254503432
oct20042326340443
93815853651482
101104131244323
11396294336aa8
12159ba33a056b
138017195c943
143b624023119
151dac34ed4b8
hex1011359c123

1104131244323 has 4 divisors (see below), whose sum is σ = 1104449532960. Its totient is φ = 1103812955688.

The previous prime is 1104131244283. The next prime is 1104131244331. The reversal of 1104131244323 is 3234421314011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1104131244323 - 214 = 1104131227939 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1104131244373) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 159139115 + ... + 159146052.

It is an arithmetic number, because the mean of its divisors is an integer number (276112383240).

Almost surely, 21104131244323 is an apocalyptic number.

1104131244323 is a deficient number, since it is larger than the sum of its proper divisors (318288637).

1104131244323 is an equidigital number, since it uses as much as digits as its factorization.

1104131244323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 318288636.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1104131244323 its reverse (3234421314011), we get a palindrome (4338552558334).

The spelling of 1104131244323 in words is "one trillion, one hundred four billion, one hundred thirty-one million, two hundred forty-four thousand, three hundred twenty-three".

Divisors: 1 3469 318285167 1104131244323