Base | Representation |
---|---|
bin | 10000000100010011011… |
… | …111000011011001011011 |
3 | 10220112221221222110020222 |
4 | 100010103133003121123 |
5 | 121042231134040210 |
6 | 2203122032510255 |
7 | 142525312630256 |
oct | 20042337033133 |
9 | 3815857873228 |
10 | 1104133502555 |
11 | 396295639706 |
12 | 159ba40ab38b |
13 | 80172270785 |
14 | 3b62445009d |
15 | 1dac37e7655 |
hex | 101137c365b |
1104133502555 has 16 divisors (see below), whose sum is σ = 1360806207840. Its totient is φ = 859410738432.
The previous prime is 1104133502509. The next prime is 1104133502611. The reversal of 1104133502555 is 5552053314011.
It is a cyclic number.
It is not a de Polignac number, because 1104133502555 - 214 = 1104133486171 is a prime.
It is a super-2 number, since 2×11041335025552 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11164916 + ... + 11263374.
It is an arithmetic number, because the mean of its divisors is an integer number (85050387990).
Almost surely, 21104133502555 is an apocalyptic number.
1104133502555 is a deficient number, since it is larger than the sum of its proper divisors (256672705285).
1104133502555 is an equidigital number, since it uses as much as digits as its factorization.
1104133502555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 159118.
The product of its (nonzero) digits is 45000, while the sum is 35.
Adding to 1104133502555 its reverse (5552053314011), we get a palindrome (6656186816566).
The spelling of 1104133502555 in words is "one trillion, one hundred four billion, one hundred thirty-three million, five hundred two thousand, five hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.138 sec. • engine limits •