11042112113 has 4 divisors (see below), whose sum is σ = 11522203968. Its totient is φ = 10562020260.

The previous prime is 11042112089. The next prime is 11042112121. The reversal of 11042112113 is 31121124011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31121124011 = 281 ⋅110751331.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11042112113 is a prime.

It is a super-2 number, since 2×11042112113² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11042112091 and 11042112100.

It is not an unprimeable number, because it can be changed into a prime (11042114113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 240045893 + ... + 240045938.

It is an arithmetic number, because the mean of its divisors is an integer number (2880550992).

Almost surely, 2^11042112113 is an apocalyptic number.

It is an amenable number.

11042112113 is a deficient number, since it is larger than the sum of its proper divisors (480091855).

11042112113 is an equidigital number, since it uses as much as digits as its factorization.

11042112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 480091854.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 11042112113 its reverse (31121124011), we get a palindrome (42163236124).

The spelling of 11042112113 in words is "eleven billion, forty-two million, one hundred twelve thousand, one hundred thirteen".