Base | Representation |
---|---|
bin | 1010000010110011100111… |
… | …0011000110110011000001 |
3 | 1110002201202200212001202001 |
4 | 2200230321303012303001 |
5 | 2421413220114212023 |
6 | 35253122553024001 |
7 | 2216566012303336 |
oct | 240547163066301 |
9 | 43081680761661 |
10 | 11043330616513 |
11 | 35784a5263488 |
12 | 12a43310b5001 |
13 | 6214c6518400 |
14 | 2a270020c98d |
15 | 1423e07906ad |
hex | a0b39cc6cc1 |
11043330616513 has 12 divisors (see below), whose sum is σ = 11959642908288. Its totient is φ = 10192581862320.
The previous prime is 11043330616511. The next prime is 11043330616567. The reversal of 11043330616513 is 31561603334011.
It is not a de Polignac number, because 11043330616513 - 21 = 11043330616511 is a prime.
It is a super-2 number, since 2×110433306165132 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11043330616511) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2673433 + ... + 5406838.
It is an arithmetic number, because the mean of its divisors is an integer number (996636909024).
Almost surely, 211043330616513 is an apocalyptic number.
11043330616513 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
11043330616513 is a deficient number, since it is larger than the sum of its proper divisors (916312291775).
11043330616513 is an equidigital number, since it uses as much as digits as its factorization.
11043330616513 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8088384 (or 8088371 counting only the distinct ones).
The product of its (nonzero) digits is 58320, while the sum is 37.
The spelling of 11043330616513 in words is "eleven trillion, forty-three billion, three hundred thirty million, six hundred sixteen thousand, five hundred thirteen".
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