Search a number
-
+
11043331105 = 52208666221
BaseRepresentation
bin10100100100011101…
…11101110000100001
31001111121222100100011
422102032331300201
5140104043043410
65023452524521
7540443523412
oct122216756041
931447870304
1011043331105
114757744124
122182480741
13106cbb9461
1476a94d809
1544979d18a
hex2923bdc21

11043331105 has 4 divisors (see below), whose sum is σ = 13251997332. Its totient is φ = 8834664880.

The previous prime is 11043331063. The next prime is 11043331129. The reversal of 11043331105 is 50113334011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 50113334011 = 133854871847.

It can be written as a sum of positive squares in 2 ways, for example, as 6386087569 + 4657243536 = 79913^2 + 68244^2 .

It is not a de Polignac number, because 11043331105 - 211 = 11043329057 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1104333106 + ... + 1104333115.

It is an arithmetic number, because the mean of its divisors is an integer number (3312999333).

Almost surely, 211043331105 is an apocalyptic number.

It is an amenable number.

11043331105 is a deficient number, since it is larger than the sum of its proper divisors (2208666227).

11043331105 is an equidigital number, since it uses as much as digits as its factorization.

11043331105 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2208666226.

The product of its (nonzero) digits is 540, while the sum is 22.

Adding to 11043331105 its reverse (50113334011), we get a palindrome (61156665116).

The spelling of 11043331105 in words is "eleven billion, forty-three million, three hundred thirty-one thousand, one hundred five".

Divisors: 1 5 2208666221 11043331105