1104333234131 has 4 divisors (see below), whose sum is σ = 1104454718664. Its totient is φ = 1104211749600.

The previous prime is 1104333234079. The next prime is 1104333234139. The reversal of 1104333234131 is 1314323334011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1104333234131 - 2¹⁴ = 1104333217747 is a prime.

It is a super-2 number, since 2×1104333234131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1104333234094 and 1104333234103.

It is not an unprimeable number, because it can be changed into a prime (1104333234139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60728630 + ... + 60746811.

It is an arithmetic number, because the mean of its divisors is an integer number (276113679666).

Almost surely, 2^{1104333234131} is an apocalyptic number.

1104333234131 is a deficient number, since it is larger than the sum of its proper divisors (121484533).

1104333234131 is an equidigital number, since it uses as much as digits as its factorization.

1104333234131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 121484532.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 1104333234131 its reverse (1314323334011), we get a palindrome (2418656568142).

The spelling of 1104333234131 in words is "one trillion, one hundred four billion, three hundred thirty-three million, two hundred thirty-four thousand, one hundred thirty-one".