Base | Representation |
---|---|
bin | 10000000100011111011… |
… | …100000010110101010011 |
3 | 10220120110221022211110200 |
4 | 100010133130002311103 |
5 | 121043134003243103 |
6 | 2203153555030243 |
7 | 142533266314566 |
oct | 20043734026523 |
9 | 3816427284420 |
10 | 1104334040403 |
11 | 396388859770 |
12 | 15a03b29b383 |
13 | 801a4985819 |
14 | 3b642d324dd |
15 | 1dad620b0a3 |
hex | 1011f702d53 |
1104334040403 has 12 divisors (see below), whose sum is σ = 1740162730488. Its totient is φ = 669293357760.
The previous prime is 1104334040377. The next prime is 1104334040417. The reversal of 1104334040403 is 3040404334011.
1104334040403 is a `hidden beast` number, since 110 + 433 + 40 + 40 + 40 + 3 = 666.
It is not a de Polignac number, because 1104334040403 - 25 = 1104334040371 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1104334040203) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5577444550 + ... + 5577444747.
It is an arithmetic number, because the mean of its divisors is an integer number (145013560874).
Almost surely, 21104334040403 is an apocalyptic number.
1104334040403 is a deficient number, since it is larger than the sum of its proper divisors (635828690085).
1104334040403 is a wasteful number, since it uses less digits than its factorization.
1104334040403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11154889314 (or 11154889311 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 27.
Adding to 1104334040403 its reverse (3040404334011), we get a palindrome (4144738374414).
The spelling of 1104334040403 in words is "one trillion, one hundred four billion, three hundred thirty-four million, forty thousand, four hundred three".
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