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1104340055035 = 5731552573001
BaseRepresentation
bin10000000100011111110…
…010111111001111111011
310220120111100122101222211
4100010133302333033323
5121043142023230120
62203154331555551
7142533401405140
oct20043762771773
93816440571884
101104340055035
11396391197638
1215a0412bbbb7
13801a5cb0389
143b643a5a3c7
151dad69e825a
hex1011fcbf3fb

1104340055035 has 8 divisors (see below), whose sum is σ = 1514523504096. Its totient is φ = 757261752000.

The previous prime is 1104340055017. The next prime is 1104340055041. The reversal of 1104340055035 is 5305500434011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1104340055035 - 25 = 1104340055003 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1104340054988 and 1104340055006.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15776286466 + ... + 15776286535.

It is an arithmetic number, because the mean of its divisors is an integer number (189315438012).

Almost surely, 21104340055035 is an apocalyptic number.

1104340055035 is a deficient number, since it is larger than the sum of its proper divisors (410183449061).

1104340055035 is an equidigital number, since it uses as much as digits as its factorization.

1104340055035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31552573013.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 1104340055035 its reverse (5305500434011), we get a palindrome (6409840489046).

The spelling of 1104340055035 in words is "one trillion, one hundred four billion, three hundred forty million, fifty-five thousand, thirty-five".

Divisors: 1 5 7 35 31552573001 157762865005 220868011007 1104340055035