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110442312553 = 145975697267
BaseRepresentation
bin110011011011011011…
…1111111001101101001
3101120001220200210010111
41212312313333031221
53302141213000203
6122423030014321
710656602111266
oct1466667771551
9346056623114
10110442312553
1142924896081
12194a2aa73a1
13a551034801
1454b9c4026d
152d15d6826d
hex19b6dff369

110442312553 has 4 divisors (see below), whose sum is σ = 110518011280. Its totient is φ = 110366613828.

The previous prime is 110442312517. The next prime is 110442312569. The reversal of 110442312553 is 355213244011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 110442312553 - 29 = 110442312041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110442312503) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37847175 + ... + 37850092.

It is an arithmetic number, because the mean of its divisors is an integer number (27629502820).

Almost surely, 2110442312553 is an apocalyptic number.

It is an amenable number.

110442312553 is a deficient number, since it is larger than the sum of its proper divisors (75698727).

110442312553 is an equidigital number, since it uses as much as digits as its factorization.

110442312553 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 75698726.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 110442312553 its reverse (355213244011), we get a palindrome (465655556564).

The spelling of 110442312553 in words is "one hundred ten billion, four hundred forty-two million, three hundred twelve thousand, five hundred fifty-three".

Divisors: 1 1459 75697267 110442312553