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1104512523043 = 7689231436441
BaseRepresentation
bin10000000100101010000…
…100111001101100100011
310220120221101011200121211
4100010222010321230203
5121044020201214133
62203223412330551
7142540564353256
oct20045204715443
93816841150554
101104512523043
1139646a585386
1215a08b013a57
1380202947b57
143b65c91309d
151dae6c14bcd
hex1012a139b23

1104512523043 has 4 divisors (see below), whose sum is σ = 1104514728408. Its totient is φ = 1104510317680.

The previous prime is 1104512523031. The next prime is 1104512523047. The reversal of 1104512523043 is 3403252154011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1104512523043 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1104512522996 and 1104512523014.

It is not an unprimeable number, because it can be changed into a prime (1104512523047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50703 + ... + 1487143.

It is an arithmetic number, because the mean of its divisors is an integer number (276128682102).

Almost surely, 21104512523043 is an apocalyptic number.

1104512523043 is a deficient number, since it is larger than the sum of its proper divisors (2205365).

1104512523043 is an equidigital number, since it uses as much as digits as its factorization.

1104512523043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2205364.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 1104512523043 its reverse (3403252154011), we get a palindrome (4507764677054).

The spelling of 1104512523043 in words is "one trillion, one hundred four billion, five hundred twelve million, five hundred twenty-three thousand, forty-three".

Divisors: 1 768923 1436441 1104512523043