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11045130457 = 43256863499
BaseRepresentation
bin10100100100101011…
…10101000011011001
31001111202100202120211
422102111311003121
5140110023133312
65023555251121
7540465026344
oct122225650331
931452322524
1011045130457
114758762a99
122182ba9aa1
13107039946a
1476ac9b45b
15449a063a7
hex2925750d9

11045130457 has 4 divisors (see below), whose sum is σ = 11301994000. Its totient is φ = 10788266916.

The previous prime is 11045130451. The next prime is 11045130539. The reversal of 11045130457 is 75403154011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 75403154011 = 292600108759.

It is a cyclic number.

It is not a de Polignac number, because 11045130457 - 27 = 11045130329 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11045130451) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 128431707 + ... + 128431792.

It is an arithmetic number, because the mean of its divisors is an integer number (2825498500).

Almost surely, 211045130457 is an apocalyptic number.

It is an amenable number.

11045130457 is a deficient number, since it is larger than the sum of its proper divisors (256863543).

11045130457 is an equidigital number, since it uses as much as digits as its factorization.

11045130457 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 256863542.

The product of its (nonzero) digits is 8400, while the sum is 31.

Adding to 11045130457 its reverse (75403154011), we get a palindrome (86448284468).

The spelling of 11045130457 in words is "eleven billion, forty-five million, one hundred thirty thousand, four hundred fifty-seven".

Divisors: 1 43 256863499 11045130457