11046661313641 has 4 divisors (see below), whose sum is σ = 11046669517312. Its totient is φ = 11046653109972.

The previous prime is 11046661313609. The next prime is 11046661313683. The reversal of 11046661313641 is 14631316664011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 11046661313641 - 2⁵ = 11046661313609 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11046661313141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1554825 + ... + 4950838.

It is an arithmetic number, because the mean of its divisors is an integer number (2761667379328).

Almost surely, 2^{11046661313641} is an apocalyptic number.

It is an amenable number.

11046661313641 is a deficient number, since it is larger than the sum of its proper divisors (8203671).

11046661313641 is an equidigital number, since it uses as much as digits as its factorization.

11046661313641 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8203670.

The product of its (nonzero) digits is 186624, while the sum is 43.

Adding to 11046661313641 its reverse (14631316664011), we get a palindrome (25677977977652).

The spelling of 11046661313641 in words is "eleven trillion, forty-six billion, six hundred sixty-one million, three hundred thirteen thousand, six hundred forty-one".