Base | Representation |
---|---|
bin | 1010000011010010001100… |
… | …1101001100000101101001 |
3 | 1110010111221221002210121210 |
4 | 2200310203031030011221 |
5 | 2422032024111400203 |
6 | 35301001425023333 |
7 | 2220306333621633 |
oct | 240644315140551 |
9 | 43114857083553 |
10 | 11051541512553 |
11 | 3580a29086183 |
12 | 12a5a42a84b49 |
13 | 62220465c189 |
14 | 2a2c7c8d3a53 |
15 | 142721548803 |
hex | a0d2334c169 |
11051541512553 has 16 divisors (see below), whose sum is σ = 15626902409856. Its totient is φ = 6923311153920.
The previous prime is 11051541512521. The next prime is 11051541512639. The reversal of 11051541512553 is 35521514515011.
It is not a de Polignac number, because 11051541512553 - 25 = 11051541512521 is a prime.
It is a super-3 number, since 3×110515415125533 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (11051541512653) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 171676926 + ... + 171741287.
It is an arithmetic number, because the mean of its divisors is an integer number (976681400616).
Almost surely, 211051541512553 is an apocalyptic number.
It is an amenable number.
11051541512553 is a deficient number, since it is larger than the sum of its proper divisors (4575360897303).
11051541512553 is a wasteful number, since it uses less digits than its factorization.
11051541512553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 343418864.
The product of its (nonzero) digits is 75000, while the sum is 39.
The spelling of 11051541512553 in words is "eleven trillion, fifty-one billion, five hundred forty-one million, five hundred twelve thousand, five hundred fifty-three".
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