Base | Representation |
---|---|
bin | 1010000011010010100100… |
… | …1110001101101001000001 |
3 | 1110010112012222000200000121 |
4 | 2200310221032031221001 |
5 | 2422032230431204403 |
6 | 35301015432220241 |
7 | 2220312000544510 |
oct | 240645116155101 |
9 | 43115188020017 |
10 | 11051642444353 |
11 | 3580a80053795 |
12 | 12a5a7083a681 |
13 | 62221c53ab34 |
14 | 2a2c8c088677 |
15 | 14272a3343bd |
hex | a0d2938da41 |
11051642444353 has 4 divisors (see below), whose sum is σ = 12630448507840. Its totient is φ = 9472836380868.
The previous prime is 11051642444303. The next prime is 11051642444383. The reversal of 11051642444353 is 35344424615011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 11051642444353 - 29 = 11051642443841 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11051642444303) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 789403031733 + ... + 789403031746.
It is an arithmetic number, because the mean of its divisors is an integer number (3157612126960).
Almost surely, 211051642444353 is an apocalyptic number.
It is an amenable number.
11051642444353 is a deficient number, since it is larger than the sum of its proper divisors (1578806063487).
11051642444353 is an equidigital number, since it uses as much as digits as its factorization.
11051642444353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1578806063486.
The product of its (nonzero) digits is 691200, while the sum is 43.
The spelling of 11051642444353 in words is "eleven trillion, fifty-one billion, six hundred forty-two million, four hundred forty-four thousand, three hundred fifty-three".
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