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11051642444353 = 71578806063479
BaseRepresentation
bin1010000011010010100100…
…1110001101101001000001
31110010112012222000200000121
42200310221032031221001
52422032230431204403
635301015432220241
72220312000544510
oct240645116155101
943115188020017
1011051642444353
113580a80053795
1212a5a7083a681
1362221c53ab34
142a2c8c088677
1514272a3343bd
hexa0d2938da41

11051642444353 has 4 divisors (see below), whose sum is σ = 12630448507840. Its totient is φ = 9472836380868.

The previous prime is 11051642444303. The next prime is 11051642444383. The reversal of 11051642444353 is 35344424615011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 11051642444353 - 29 = 11051642443841 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11051642444303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 789403031733 + ... + 789403031746.

It is an arithmetic number, because the mean of its divisors is an integer number (3157612126960).

Almost surely, 211051642444353 is an apocalyptic number.

It is an amenable number.

11051642444353 is a deficient number, since it is larger than the sum of its proper divisors (1578806063487).

11051642444353 is an equidigital number, since it uses as much as digits as its factorization.

11051642444353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1578806063486.

The product of its (nonzero) digits is 691200, while the sum is 43.

The spelling of 11051642444353 in words is "eleven trillion, fifty-one billion, six hundred forty-two million, four hundred forty-four thousand, three hundred fifty-three".

Divisors: 1 7 1578806063479 11051642444353