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11052125050555 = 519346724524581
BaseRepresentation
bin1010000011010100010111…
…1111001101011010111011
31110010120110121010121021101
42200311011333031122323
52422034223003104210
635301135352152231
72220326650615621
oct240650577153273
943116417117241
1011052125050555
1135811a850a996
1212a5b86398677
13622298512b34
142a2cd61d3511
151427578b3a3a
hexa0d45fcd6bb

11052125050555 has 16 divisors (see below), whose sum is σ = 13359815093664. Its totient is φ = 8777052887040.

The previous prime is 11052125050523. The next prime is 11052125050573. The reversal of 11052125050555 is 55505052125011.

It is not a de Polignac number, because 11052125050555 - 25 = 11052125050523 is a prime.

It is a super-4 number, since 4×110521250505554 (a number of 53 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 11811636 + ... + 12712945.

It is an arithmetic number, because the mean of its divisors is an integer number (834988443354).

Almost surely, 211052125050555 is an apocalyptic number.

11052125050555 is a deficient number, since it is larger than the sum of its proper divisors (2307690043109).

11052125050555 is a wasteful number, since it uses less digits than its factorization.

11052125050555 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 24525246.

The product of its (nonzero) digits is 62500, while the sum is 37.

Adding to 11052125050555 its reverse (55505052125011), we get a palindrome (66557177175566).

The spelling of 11052125050555 in words is "eleven trillion, fifty-two billion, one hundred twenty-five million, fifty thousand, five hundred fifty-five".

Divisors: 1 5 193 467 965 2335 90131 450655 24524581 122622905 4733244133 11452979327 23666220665 57264896635 2210425010111 11052125050555