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11052132001 = 71155663831
BaseRepresentation
bin10100100101100001…
…00010011010100001
31001112020112110220021
422102300202122201
5140113321211001
65024405313441
7540611400121
oct122260423241
931466473807
1011052132001
114761705399
122185405881
13107197b2a1
1476bba0c81
1544a43aba1
hex292c226a1

11052132001 has 4 divisors (see below), whose sum is σ = 11207795904. Its totient is φ = 10896468100.

The previous prime is 11052131963. The next prime is 11052132131. The reversal of 11052132001 is 10023125011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11052132001 - 219 = 11051607713 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11052142001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77831845 + ... + 77831986.

It is an arithmetic number, because the mean of its divisors is an integer number (2801948976).

Almost surely, 211052132001 is an apocalyptic number.

It is an amenable number.

11052132001 is a deficient number, since it is larger than the sum of its proper divisors (155663903).

11052132001 is an equidigital number, since it uses as much as digits as its factorization.

11052132001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 155663902.

The product of its (nonzero) digits is 60, while the sum is 16.

Adding to 11052132001 its reverse (10023125011), we get a palindrome (21075257012).

The spelling of 11052132001 in words is "eleven billion, fifty-two million, one hundred thirty-two thousand, one".

Divisors: 1 71 155663831 11052132001