11053113 has 4 divisors (see below), whose sum is σ = 14737488. Its totient is φ = 7368740.

The previous prime is 11053073. The next prime is 11053129. The reversal of 11053113 is 31135011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11053113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11053092 and 11053101.

It is not an unprimeable number, because it can be changed into a prime (11053153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1842183 + ... + 1842188.

It is an arithmetic number, because the mean of its divisors is an integer number (3684372).

Almost surely, 2^11053113 is an apocalyptic number.

It is an amenable number.

11053113 is a deficient number, since it is larger than the sum of its proper divisors (3684375).

11053113 is an equidigital number, since it uses as much as digits as its factorization.

11053113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3684374.

The product of its (nonzero) digits is 45, while the sum is 15.

The square root of 11053113 is about 3324.6222341794. The cubic root of 11053113 is about 222.7553807143.

Adding to 11053113 its reverse (31135011), we get a palindrome (42188124).

The spelling of 11053113 in words is "eleven million, fifty-three thousand, one hundred thirteen".