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1105334211403 = 29163233834189
BaseRepresentation
bin10000000101011011000…
…011011001001101001011
310220200001122022210011001
4100011123003121031023
5121102211024231103
62203441124115431
7142600132530202
oct20053303311513
93820048283131
101105334211403
11396851389a74
1215a27a235b77
1380303c52796
143b6d9ac6239
151db43e2301d
hex1015b0d934b

1105334211403 has 8 divisors (see below), whose sum is σ = 1150464214800. Its totient is φ = 1060671876768.

The previous prime is 1105334211391. The next prime is 1105334211427. The reversal of 1105334211403 is 3041124335011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1105334211403 - 29 = 1105334210891 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1105334211473) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 116912368 + ... + 116921821.

It is an arithmetic number, because the mean of its divisors is an integer number (143808026850).

Almost surely, 21105334211403 is an apocalyptic number.

1105334211403 is a deficient number, since it is larger than the sum of its proper divisors (45130003397).

1105334211403 is a wasteful number, since it uses less digits than its factorization.

1105334211403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 233834381.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 1105334211403 its reverse (3041124335011), we get a palindrome (4146458546414).

The spelling of 1105334211403 in words is "one trillion, one hundred five billion, three hundred thirty-four million, two hundred eleven thousand, four hundred three".

Divisors: 1 29 163 4727 233834189 6781191481 38114972807 1105334211403