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1105351323113 = 1958176385427
BaseRepresentation
bin10000000101011100000…
…100101010110111101001
310220200002211112011000002
4100011130010222313221
5121102224414314423
62203442534552345
7142600431136442
oct20053404526751
93820084464002
101105351323113
11396860007284
1215a283b086b5
138030766435b
143b6dc09c2c9
151db456a3228
hex1015c12ade9

1105351323113 has 4 divisors (see below), whose sum is σ = 1163527708560. Its totient is φ = 1047174937668.

The previous prime is 1105351323107. The next prime is 1105351323137. The reversal of 1105351323113 is 3113231535011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1105351323113 - 28 = 1105351322857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1105351323313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 29088192695 + ... + 29088192732.

It is an arithmetic number, because the mean of its divisors is an integer number (290881927140).

Almost surely, 21105351323113 is an apocalyptic number.

It is an amenable number.

1105351323113 is a deficient number, since it is larger than the sum of its proper divisors (58176385447).

1105351323113 is an equidigital number, since it uses as much as digits as its factorization.

1105351323113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58176385446.

The product of its (nonzero) digits is 4050, while the sum is 29.

Adding to 1105351323113 its reverse (3113231535011), we get a palindrome (4218582858124).

The spelling of 1105351323113 in words is "one trillion, one hundred five billion, three hundred fifty-one million, three hundred twenty-three thousand, one hundred thirteen".

Divisors: 1 19 58176385427 1105351323113