Base | Representation |
---|---|
bin | 10000000101011100110… |
… | …101101010011001101011 |
3 | 10220200010201200122110212 |
4 | 100011130311222121223 |
5 | 121102241211310001 |
6 | 2203444114131335 |
7 | 142600645250132 |
oct | 20053465523153 |
9 | 3820121618425 |
10 | 1105364166251 |
11 | 396867289544 |
12 | 15a288280b4b |
13 | 8030a210047 |
14 | 3b6dda82919 |
15 | 1db4688d7bb |
hex | 1015cd6a66b |
1105364166251 has 4 divisors (see below), whose sum is σ = 1105416418392. Its totient is φ = 1105311914112.
The previous prime is 1105364166229. The next prime is 1105364166253. The reversal of 1105364166251 is 1526614635011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1105364166251 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1105364166199 and 1105364166208.
It is not an unprimeable number, because it can be changed into a prime (1105364166253) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26094326 + ... + 26136651.
It is an arithmetic number, because the mean of its divisors is an integer number (276354104598).
Almost surely, 21105364166251 is an apocalyptic number.
1105364166251 is a deficient number, since it is larger than the sum of its proper divisors (52252141).
1105364166251 is an equidigital number, since it uses as much as digits as its factorization.
1105364166251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52252140.
The product of its (nonzero) digits is 129600, while the sum is 41.
The spelling of 1105364166251 in words is "one trillion, one hundred five billion, three hundred sixty-four million, one hundred sixty-six thousand, two hundred fifty-one".
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