11054125650131 has 4 divisors (see below), whose sum is σ = 11635921737000. Its totient is φ = 10472329563264.

The previous prime is 11054125650119. The next prime is 11054125650163. The reversal of 11054125650131 is 13105652145011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11054125650131 - 2³⁴ = 11036945780947 is a prime.

It is a super-3 number, since 3×11054125650131³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11054125650091 and 11054125650100.

It is not an unprimeable number, because it can be changed into a prime (11054125658131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 290898043406 + ... + 290898043443.

It is an arithmetic number, because the mean of its divisors is an integer number (2908980434250).

Almost surely, 2^{11054125650131} is an apocalyptic number.

11054125650131 is a deficient number, since it is larger than the sum of its proper divisors (581796086869).

11054125650131 is an equidigital number, since it uses as much as digits as its factorization.

11054125650131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 581796086868.

The product of its (nonzero) digits is 18000, while the sum is 35.

Adding to 11054125650131 its reverse (13105652145011), we get a palindrome (24159777795142).

The spelling of 11054125650131 in words is "eleven trillion, fifty-four billion, one hundred twenty-five million, six hundred fifty thousand, one hundred thirty-one".