11054130042433 has 16 divisors (see below), whose sum is σ = 11572438176000. Its totient is φ = 10538966623680.

The previous prime is 11054130042409. The next prime is 11054130042457. The reversal of 11054130042433 is 33424003145011.

It is an interprime number because it is at equal distance from previous prime (11054130042409) and next prime (11054130042457).

It is a de Polignac number, because none of the positive numbers 2^k-11054130042433 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11054130042395 and 11054130042404.

It is not an unprimeable number, because it can be changed into a prime (11054130042233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 223070143 + ... + 223119691.

It is an arithmetic number, because the mean of its divisors is an integer number (723277386000).

Almost surely, 2^{11054130042433} is an apocalyptic number.

It is an amenable number.

11054130042433 is a deficient number, since it is larger than the sum of its proper divisors (518308133567).

11054130042433 is a wasteful number, since it uses less digits than its factorization.

11054130042433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81072.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 11054130042433 its reverse (33424003145011), we get a palindrome (44478133187444).

The spelling of 11054130042433 in words is "eleven trillion, fifty-four billion, one hundred thirty million, forty-two thousand, four hundred thirty-three".