110553401353 has 4 divisors (see below), whose sum is σ = 111885370128. Its totient is φ = 109221432580.

The previous prime is 110553401327. The next prime is 110553401393. The reversal of 110553401353 is 353104355011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 353104355011 = 227 ⋅1555525793.

It is a cyclic number.

It is not a de Polignac number, because 110553401353 - 2¹⁷ = 110553270281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110553401323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 665984263 + ... + 665984428.

It is an arithmetic number, because the mean of its divisors is an integer number (27971342532).

Almost surely, 2^110553401353 is an apocalyptic number.

It is an amenable number.

110553401353 is a deficient number, since it is larger than the sum of its proper divisors (1331968775).

110553401353 is an equidigital number, since it uses as much as digits as its factorization.

110553401353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1331968774.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 110553401353 its reverse (353104355011), we get a palindrome (463657756364).

The spelling of 110553401353 in words is "one hundred ten billion, five hundred fifty-three million, four hundred one thousand, three hundred fifty-three".