Base | Representation |
---|---|
bin | 10100100111001111… |
… | …00010110010001001 |
3 | 1001120020200001122022 |
4 | 22103213202302021 |
5 | 140131014121213 |
6 | 5030042334225 |
7 | 541145064230 |
oct | 122347426211 |
9 | 31506601568 |
10 | 11066551433 |
11 | 4769863983 |
12 | 218a1ba375 |
13 | 10749595b2 |
14 | 76da75b17 |
15 | 44b838308 |
hex | 2939e2c89 |
11066551433 has 4 divisors (see below), whose sum is σ = 12647487360. Its totient is φ = 9485615508.
The previous prime is 11066551417. The next prime is 11066551439. The reversal of 11066551433 is 33415566011.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 11066551433 - 24 = 11066551417 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 11066551393 and 11066551402.
It is not an unprimeable number, because it can be changed into a prime (11066551439) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 790467953 + ... + 790467966.
It is an arithmetic number, because the mean of its divisors is an integer number (3161871840).
Almost surely, 211066551433 is an apocalyptic number.
It is an amenable number.
11066551433 is a deficient number, since it is larger than the sum of its proper divisors (1580935927).
11066551433 is an equidigital number, since it uses as much as digits as its factorization.
11066551433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1580935926.
The product of its (nonzero) digits is 32400, while the sum is 35.
The spelling of 11066551433 in words is "eleven billion, sixty-six million, five hundred fifty-one thousand, four hundred thirty-three".
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