Search a number
-
+
11066551433 = 71580935919
BaseRepresentation
bin10100100111001111…
…00010110010001001
31001120020200001122022
422103213202302021
5140131014121213
65030042334225
7541145064230
oct122347426211
931506601568
1011066551433
114769863983
12218a1ba375
1310749595b2
1476da75b17
1544b838308
hex2939e2c89

11066551433 has 4 divisors (see below), whose sum is σ = 12647487360. Its totient is φ = 9485615508.

The previous prime is 11066551417. The next prime is 11066551439. The reversal of 11066551433 is 33415566011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11066551433 - 24 = 11066551417 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11066551393 and 11066551402.

It is not an unprimeable number, because it can be changed into a prime (11066551439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 790467953 + ... + 790467966.

It is an arithmetic number, because the mean of its divisors is an integer number (3161871840).

Almost surely, 211066551433 is an apocalyptic number.

It is an amenable number.

11066551433 is a deficient number, since it is larger than the sum of its proper divisors (1580935927).

11066551433 is an equidigital number, since it uses as much as digits as its factorization.

11066551433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1580935926.

The product of its (nonzero) digits is 32400, while the sum is 35.

The spelling of 11066551433 in words is "eleven billion, sixty-six million, five hundred fifty-one thousand, four hundred thirty-three".

Divisors: 1 7 1580935919 11066551433