1110013313001 has 4 divisors (see below), whose sum is σ = 1480017750672. Its totient is φ = 740008875332.

The previous prime is 1110013312981. The next prime is 1110013313009. The reversal of 1110013313001 is 1003133100111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1110013313001 - 2¹⁷ = 1110013181929 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1110013313009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 185002218831 + ... + 185002218836.

It is an arithmetic number, because the mean of its divisors is an integer number (370004437668).

Almost surely, 2^{1110013313001} is an apocalyptic number.

It is an amenable number.

1110013313001 is a deficient number, since it is larger than the sum of its proper divisors (370004437671).

1110013313001 is an equidigital number, since it uses as much as digits as its factorization.

1110013313001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 370004437670.

The product of its (nonzero) digits is 27, while the sum is 15.

Adding to 1110013313001 its reverse (1003133100111), we get a palindrome (2113146413112).

The spelling of 1110013313001 in words is "one trillion, one hundred ten billion, thirteen million, three hundred thirteen thousand, one".