1110022313131 has 4 divisors (see below), whose sum is σ = 1110129644592. Its totient is φ = 1109914981672.

The previous prime is 1110022313053. The next prime is 1110022313159. The reversal of 1110022313131 is 1313132200111.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1110022313131 - 2¹⁵ = 1110022280363 is a prime.

It is a super-2 number, since 2×1110022313131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1110022313099 and 1110022313108.

It is not an unprimeable number, because it can be changed into a prime (1110022113131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53650216 + ... + 53670901.

It is an arithmetic number, because the mean of its divisors is an integer number (277532411148).

Almost surely, 2^{1110022313131} is an apocalyptic number.

1110022313131 is a deficient number, since it is larger than the sum of its proper divisors (107331461).

1110022313131 is a wasteful number, since it uses less digits than its factorization.

1110022313131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 107331460.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1110022313131 its reverse (1313132200111), we get a palindrome (2423154513242).

The spelling of 1110022313131 in words is "one trillion, one hundred ten billion, twenty-two million, three hundred thirteen thousand, one hundred thirty-one".