Base | Representation |
---|---|
bin | 11001001111010011101101… |
… | …000101000011000100110011 |
3 | 112120000210102202100111211112 |
4 | 121033103231011003010303 |
5 | 104022133333223240311 |
6 | 1032030043102103535 |
7 | 32244465413541656 |
oct | 3117235505030463 |
9 | 476023382314745 |
10 | 111003112321331 |
11 | 3240717907317a |
12 | 1054919187abab |
13 | 49c27192ba349 |
14 | 1d5a81786b89d |
15 | cc76a430828b |
hex | 64f4ed143133 |
111003112321331 has 4 divisors (see below), whose sum is σ = 111148977121464. Its totient is φ = 110857247521200.
The previous prime is 111003112321319. The next prime is 111003112321333. The reversal of 111003112321331 is 133123211300111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-111003112321331 is a prime.
It is a super-2 number, since 2×1110031123213312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 111003112321297 and 111003112321306.
It is not an unprimeable number, because it can be changed into a prime (111003112321333) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 72932398925 + ... + 72932400446.
It is an arithmetic number, because the mean of its divisors is an integer number (27787244280366).
Almost surely, 2111003112321331 is an apocalyptic number.
111003112321331 is a deficient number, since it is larger than the sum of its proper divisors (145864800133).
111003112321331 is an equidigital number, since it uses as much as digits as its factorization.
111003112321331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 145864800132.
The product of its (nonzero) digits is 324, while the sum is 23.
Adding to 111003112321331 its reverse (133123211300111), we get a palindrome (244126323621442).
The spelling of 111003112321331 in words is "one hundred eleven trillion, three billion, one hundred twelve million, three hundred twenty-one thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •