Base | Representation |
---|---|
bin | 10100101011010000… |
… | …10101011011011001 |
3 | 1001122121012100020000 |
4 | 22111220111123121 |
5 | 140213140011210 |
6 | 5033250123213 |
7 | 542035051314 |
oct | 122550253331 |
9 | 31577170200 |
10 | 11100313305 |
11 | 4786923754 |
12 | 2199580509 |
13 | 107b94a933 |
14 | 77434397b |
15 | 44e7a6ac0 |
hex | 295a156d9 |
11100313305 has 40 divisors (see below), whose sum is σ = 20150275200. Its totient is φ = 5845211424.
The previous prime is 11100313283. The next prime is 11100313321. The reversal of 11100313305 is 50331300111.
11100313305 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11100313305 - 27 = 11100313177 is a prime.
It is a Curzon number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 141475 + ... + 205464.
It is an arithmetic number, because the mean of its divisors is an integer number (503756880).
Almost surely, 211100313305 is an apocalyptic number.
11100313305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
11100313305 is a deficient number, since it is larger than the sum of its proper divisors (9049961895).
11100313305 is an equidigital number, since it uses as much as digits as its factorization.
11100313305 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 347035 (or 347026 counting only the distinct ones).
The product of its (nonzero) digits is 135, while the sum is 18.
Adding to 11100313305 its reverse (50331300111), we get a palindrome (61431613416).
The spelling of 11100313305 in words is "eleven billion, one hundred million, three hundred thirteen thousand, three hundred five".
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