11100314331401 has 4 divisors (see below), whose sum is σ = 11753273997972. Its totient is φ = 10447354664832.

The previous prime is 11100314331397. The next prime is 11100314331419. The reversal of 11100314331401 is 10413341300111.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6862953836176 + 4237360495225 = 2619724^2 + 2058485^2 .

It is a cyclic number.

It is not a de Polignac number, because 11100314331401 - 2² = 11100314331397 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11100314331461) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 326479833260 + ... + 326479833293.

It is an arithmetic number, because the mean of its divisors is an integer number (2938318499493).

Almost surely, 2^{11100314331401} is an apocalyptic number.

It is an amenable number.

11100314331401 is a deficient number, since it is larger than the sum of its proper divisors (652959666571).

11100314331401 is an equidigital number, since it uses as much as digits as its factorization.

11100314331401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 652959666570.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 11100314331401 its reverse (10413341300111), we get a palindrome (21513655631512).

The spelling of 11100314331401 in words is "eleven trillion, one hundred billion, three hundred fourteen million, three hundred thirty-one thousand, four hundred one".