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11101331203 = 21187523969
BaseRepresentation
bin10100101011011000…
…01101111100000011
31001122200010001111221
422111230031330003
5140213420044303
65033324015511
7542046521044
oct122554157403
931580101457
1011101331203
114787459496
122199991597
13107bc16041
1477452a8cb
1544e9084bd
hex295b0df03

11101331203 has 4 divisors (see below), whose sum is σ = 11101876360. Its totient is φ = 11100786048.

The previous prime is 11101331201. The next prime is 11101331221. The reversal of 11101331203 is 30213310111.

11101331203 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11101331203 - 21 = 11101331201 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11101331201) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 240798 + ... + 283171.

It is an arithmetic number, because the mean of its divisors is an integer number (2775469090).

Almost surely, 211101331203 is an apocalyptic number.

11101331203 is a deficient number, since it is larger than the sum of its proper divisors (545157).

11101331203 is an equidigital number, since it uses as much as digits as its factorization.

11101331203 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 545156.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 11101331203 its reverse (30213310111), we get a palindrome (41314641314).

The spelling of 11101331203 in words is "eleven billion, one hundred one million, three hundred thirty-one thousand, two hundred three".

Divisors: 1 21187 523969 11101331203