11102033121233 has 4 divisors (see below), whose sum is σ = 11104723223040. Its totient is φ = 11099343019428.

The previous prime is 11102033121227. The next prime is 11102033121307. The reversal of 11102033121233 is 33212133020111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11102033121233 - 2⁴ = 11102033121217 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11102033121199 and 11102033121208.

It is not an unprimeable number, because it can be changed into a prime (11102033121203) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1345044713 + ... + 1345052966.

It is an arithmetic number, because the mean of its divisors is an integer number (2776180805760).

Almost surely, 2^{11102033121233} is an apocalyptic number.

It is an amenable number.

11102033121233 is a deficient number, since it is larger than the sum of its proper divisors (2690101807).

11102033121233 is an equidigital number, since it uses as much as digits as its factorization.

11102033121233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2690101806.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 11102033121233 its reverse (33212133020111), we get a palindrome (44314166141344).

The spelling of 11102033121233 in words is "eleven trillion, one hundred two billion, thirty-three million, one hundred twenty-one thousand, two hundred thirty-three".