1110221211121 has 4 divisors (see below), whose sum is σ = 1211150412144. Its totient is φ = 1009292010100.

The previous prime is 1110221211101. The next prime is 1110221211149. The reversal of 1110221211121 is 1211121220111.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1110221211121 - 2⁵ = 1110221211089 is a prime.

It is a super-3 number, since 3×1110221211121³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1110221211095 and 1110221211104.

It is not an unprimeable number, because it can be changed into a prime (1110221211101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50464600495 + ... + 50464600516.

It is an arithmetic number, because the mean of its divisors is an integer number (302787603036).

Almost surely, 2^{1110221211121} is an apocalyptic number.

1110221211121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1110221211121 is a deficient number, since it is larger than the sum of its proper divisors (100929201023).

1110221211121 is a wasteful number, since it uses less digits than its factorization.

1110221211121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100929201022.

The product of its (nonzero) digits is 16, while the sum is 16.

Adding to 1110221211121 its reverse (1211121220111), we get a palindrome (2321342431232).

The spelling of 1110221211121 in words is "one trillion, one hundred ten billion, two hundred twenty-one million, two hundred eleven thousand, one hundred twenty-one".