Base | Representation |
---|---|
bin | 110011101100110010… |
… | …0010000010110000001 |
3 | 101121120110212221222112 |
4 | 1213121210100112001 |
5 | 3304334212424101 |
6 | 123000500545105 |
7 | 11010200224310 |
oct | 1473144202601 |
9 | 347513787875 |
10 | 111024342401 |
11 | 430a338a785 |
12 | 196259b2195 |
13 | a6147aab7b |
14 | 553326a277 |
15 | 2d4bed66bb |
hex | 19d9910581 |
111024342401 has 4 divisors (see below), whose sum is σ = 126884962752. Its totient is φ = 95163722052.
The previous prime is 111024342391. The next prime is 111024342427. The reversal of 111024342401 is 104243420111.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 104243420111 = 59 ⋅1766837629.
It is a de Polignac number, because none of the positive numbers 2k-111024342401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (111024342461) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7930310165 + ... + 7930310178.
It is an arithmetic number, because the mean of its divisors is an integer number (31721240688).
Almost surely, 2111024342401 is an apocalyptic number.
It is an amenable number.
111024342401 is a deficient number, since it is larger than the sum of its proper divisors (15860620351).
111024342401 is an equidigital number, since it uses as much as digits as its factorization.
111024342401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15860620350.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 111024342401 its reverse (104243420111), we get a palindrome (215267762512).
The spelling of 111024342401 in words is "one hundred eleven billion, twenty-four million, three hundred forty-two thousand, four hundred one".
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