Base | Representation |
---|---|
bin | 11001001111101100111100… |
… | …001110111111000001010011 |
3 | 112120010101101020122211010221 |
4 | 121033230330032333001103 |
5 | 104023104332243130003 |
6 | 1032050324022133511 |
7 | 32246445053242423 |
oct | 3117547416770123 |
9 | 476111336584127 |
10 | 111030210130003 |
11 | 3241771408097a |
12 | 10552494881297 |
13 | 49c5147325168 |
14 | 1d5bc68690483 |
15 | cc823d25d7bd |
hex | 64fb3c3bf053 |
111030210130003 has 4 divisors (see below), whose sum is σ = 114611829811648. Its totient is φ = 107448590448360.
The previous prime is 111030210129989. The next prime is 111030210130067. The reversal of 111030210130003 is 300031012030111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 111030210130003 - 29 = 111030210129491 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (111030210130093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1790809840776 + ... + 1790809840837.
It is an arithmetic number, because the mean of its divisors is an integer number (28652957452912).
Almost surely, 2111030210130003 is an apocalyptic number.
111030210130003 is a deficient number, since it is larger than the sum of its proper divisors (3581619681645).
111030210130003 is an equidigital number, since it uses as much as digits as its factorization.
111030210130003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3581619681644.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 111030210130003 its reverse (300031012030111), we get a palindrome (411061222160114).
The spelling of 111030210130003 in words is "one hundred eleven trillion, thirty billion, two hundred ten million, one hundred thirty thousand, three".
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