Base | Representation |
---|---|
bin | 10000001010000011001… |
… | …010011111111111010011 |
3 | 10221010212212100012110222 |
4 | 100022003022133333103 |
5 | 121142344321131011 |
6 | 2210022111543255 |
7 | 143134215250235 |
oct | 20120312377723 |
9 | 3833785305428 |
10 | 1110302130131 |
11 | 398970674927 |
12 | 15b225b2ab2b |
13 | 8091625ac6c |
14 | 3ba4b7d6255 |
15 | 1dd3513dddb |
hex | 1028329ffd3 |
1110302130131 has 4 divisors (see below), whose sum is σ = 1112527185000. Its totient is φ = 1108077075264.
The previous prime is 1110302130109. The next prime is 1110302130149. The reversal of 1110302130131 is 1310312030111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1110302130131 - 238 = 835424223187 is a prime.
It is a super-2 number, since 2×11103021301312 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1110302130191) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1112526686 + ... + 1112527683.
It is an arithmetic number, because the mean of its divisors is an integer number (278131796250).
Almost surely, 21110302130131 is an apocalyptic number.
1110302130131 is a deficient number, since it is larger than the sum of its proper divisors (2225054869).
1110302130131 is an equidigital number, since it uses as much as digits as its factorization.
1110302130131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2225054868.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1110302130131 its reverse (1310312030111), we get a palindrome (2420614160242).
The spelling of 1110302130131 in words is "one trillion, one hundred ten billion, three hundred two million, one hundred thirty thousand, one hundred thirty-one".
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