Base | Representation |
---|---|
bin | 1010000110010011000001… |
… | …0101001001111000000011 |
3 | 1110022110120011022001021001 |
4 | 2201210300111021320003 |
5 | 2423404030113441003 |
6 | 35340441453112431 |
7 | 2224121104640215 |
oct | 241446025117003 |
9 | 43273504261231 |
10 | 11103301312003 |
11 | 35a097a14563a |
12 | 12b3a89188717 |
13 | 627062b85044 |
14 | 2a558cc345b5 |
15 | 143c5065561d |
hex | a1930549e03 |
11103301312003 has 4 divisors (see below), whose sum is σ = 11103644430648. Its totient is φ = 11102958193360.
The previous prime is 11103301311997. The next prime is 11103301312027. The reversal of 11103301312003 is 30021310330111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 11103301312003 - 229 = 11102764441091 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11103301312703) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171510778 + ... + 171575503.
It is an arithmetic number, because the mean of its divisors is an integer number (2775911107662).
Almost surely, 211103301312003 is an apocalyptic number.
11103301312003 is a deficient number, since it is larger than the sum of its proper divisors (343118645).
11103301312003 is an equidigital number, since it uses as much as digits as its factorization.
11103301312003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 343118644.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 11103301312003 its reverse (30021310330111), we get a palindrome (41124611642114).
The spelling of 11103301312003 in words is "eleven trillion, one hundred three billion, three hundred one million, three hundred twelve thousand, three".
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