Base | Representation |
---|---|
bin | 10100101011100111… |
… | …01110111011010011 |
3 | 1001122210211011000122 |
4 | 22111303232323103 |
5 | 140214421120311 |
6 | 5033434140455 |
7 | 542102334623 |
oct | 122563567323 |
9 | 31583734018 |
10 | 11103301331 |
11 | 47885846a1 |
12 | 219a58172b |
13 | 107c4559b5 |
14 | 7748c0883 |
15 | 44eb970db |
hex | 295ceeed3 |
11103301331 has 4 divisors (see below), whose sum is σ = 11103851472. Its totient is φ = 11102751192.
The previous prime is 11103301283. The next prime is 11103301357. The reversal of 11103301331 is 13310330111.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11103301331 is a prime.
It is a super-2 number, since 2×111033013312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (11103301931) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 243596 + ... + 285561.
It is an arithmetic number, because the mean of its divisors is an integer number (2775962868).
Almost surely, 211103301331 is an apocalyptic number.
11103301331 is a deficient number, since it is larger than the sum of its proper divisors (550141).
11103301331 is an equidigital number, since it uses as much as digits as its factorization.
11103301331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 550140.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 11103301331 its reverse (13310330111), we get a palindrome (24413631442).
The spelling of 11103301331 in words is "eleven billion, one hundred three million, three hundred one thousand, three hundred thirty-one".
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